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C语言程序设计-实现数组的逆置

Soy丶sauce 2022-03-22 阅读 78

c语言实现数组的逆置

获取一个数组

   int a[10] = {0};
    printf("请输入一组数字:\n");
    for (int i = 0; i <10; ++i) {
        scanf("%d",&a[i]);
    }
    printf("原数字顺序\n");
    for (int i = 0; i < 10; ++i) {
        printf("%d ",a[i]);
    }
    printf("\n");

实现数组逆置的思路:
1.找到数组的中间位置作为遍历长度
2.第一位和最后一位交换

    int b = sizeof(a)/ sizeof(a[0]);//获取数组长度
    for (int i = 0; i < b/2; ++i) {
        temp = a[i];
        a[i] = a[b-i-1];
        a[b-i-1] = temp;
    }
    for (int i = 0; i < 10; ++i) {
        printf("%d ",a[i]);
    }

结果:
在这里插入图片描述
完整代码

#include <stdio.h>
int main(){
    //逆置
    int i,temp;
    int a[10] = {0};
    printf("请输入一组数字:\n");
    for (int i = 0; i <10; ++i) {
        scanf("%d",&a[i]);
    }
    printf("原数字顺序\n");
    for (int i = 0; i < 10; ++i) {
        printf("%d ",a[i]);
    }
    printf("\n");
    printf("逆置后\n");
    int b = sizeof(a)/ sizeof(a[0]);//获取数组长度
    for (int i = 0; i < b/2; ++i) {
        temp = a[i];
        a[i] = a[b-i-1];
        a[b-i-1] = temp;
    }
    for (int i = 0; i < 10; ++i) {
        printf("%d ",a[i]);
    }
    return 0;
}
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