博客分类:
- java基础
XML EXT
解析xml字符串,如下
1. public static void
2. //System.out.println("cccc");
3. "<?xml version='1.0' encoding='UTF-8'?>"
4. "<ROOT test='test123' cod='cod123'><Name>AAA</Name><Number>BBB</Number>"
5. "<Recording>http://10.15.57.174/wav/2008/10/29/WG37100/ext37102/10.15.57.71!1~R!10292008_064002!37102!67256479!Ext!NA!1179371583!R.wav</Recording>"
6. "<Orders>有</Orders></ROOT>";
7. try
8. new
9. Document doc;
10. doc = DocumentHelper.parseText(fStr);
11.
12. //Document doc = reader.read(ffile); //读取一个xml的文件
13. Element root = doc.getRootElement();
14. "test");
15. "-***--"+testCmd.getValue());
16. "Name");
17. "节点内容*--"+eName.getTextTrim());
18.
19. catch
20. e.printStackTrace();
21. }
22. }
解析xml文件,xml文件如下
1. <?xml version="1.0" encoding="UTF-8"?>
2. <students>
3. <student age="25">
4. <name>AAA</name>
5. <collage leader='班长'>xxx学校</collage>
6. <telephone>13728704450</telephone>
7. <notes>男,1958年出生</notes>
8. </student>
9. <student age="21">
10. <name>BBB</name>
11. <collage leader='学生'>YYY学校</collage>
12. <telephone>1372sadgasg4450</telephone>
13. <notes>男,1968年出生,出生地长沙</notes>
14. </student>
15. <student age="29">
16. <name>CCC</name>
17. <collage leader='班主任'>北京大学</collage>
18. <telephone>13828704450</telephone>
19. <notes>女,漂亮</notes>
20. </student>
21. </students>
解析的代码如下
1. public void
2. new
3. try
4. new
5. Element root = document.getRootElement();
6. // 用于记录学生编号的变量
7. int num = -1;
8. // 遍历根结点(students)的所有孩子节点(肯定是student节点)
9. for
10. Element element = (Element) iter.next();
11. num++;
12. // 获取person节点的age属性的值
13. "age");
14. if (ageAttr != null) {
15. String age = ageAttr.getValue();
16. if (age != null && !age.equals("")) {
17. "-"
18. + num, age);
19. else
20. "-"
21. "20");
22. }
23. else
24. "-age" + num, "20");
25. }
26. // 遍历student结点的所有孩子节点(即name,college,telphone,notes),并进行处理
27. for
28. .hasNext();) {
29. Element elementInner = (Element) iterInner.next();
30. if (elementInner.getName().equals("collage")) {
31. hm.put(elementInner.getName() + num, elementInner
32. .getText());
33. // 获取college节点的leader属性的值
34. "leader");
35. if (leaderAttr != null) {
36. String leader = leaderAttr.getValue();
37. if (leader != null && !leader.equals("")) {
38. "-"
39. + leaderAttr.getName() + num, leader);
40. else
41. "-"
42. "leader");
43. }
44. else
45. "-leader"
46. "leader");
47. }
48. else
49. hm.put(elementInner.getName() + num, elementInner
50. .getText());
51. }
52. }
53. }
54. catch
55. e.printStackTrace();
56. }
57. }