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剑指 Offer 27. 二叉树的镜像

_铁马冰河_ 2022-01-31 阅读 42

思路:递归

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    TreeNode* mirrorTree(TreeNode* root) {
        if(root==NULL) return NULL;
        TreeNode *right=mirrorTree(root->left);
        TreeNode *left=mirrorTree(root->right);
        root->right=right;
        root->left=left;
        return root;
    }
};

 

 

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