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【扑克牌大小___逻辑题】

想溜了的蜗牛 2022-04-14 阅读 75
java

 超强逻辑题,兄弟们谨慎理解~~~话不多说,上代码

public class Main3 {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        String str = scanner.nextLine();
        String[] arr = str.split("-");
        String ret = judge(arr[0],arr[1]);
        judgeSame(arr[0],arr[1]);
        System.out.println(ret);
    }
    private static String tmp = "3,4,5,6,7,8,9,10,J,Q,K,A,2,joker,JOKER";
    private static String judge(String s1, String s2) {
        String ret = "ERROR";
        String[] arr1 = s1.split(" ");
        String[] arr2 = s2.split(" ");
        if(arr1.length != arr2.length){//炸弹-王炸或者炸弹-普通或者王炸-普通
            if(arr1.length == 2 || arr2.length == 2){
                String[] cur = new String[2];
                if(arr1.length == 2){
                    cur = arr1;
                }else {
                    cur = arr2;
                }
                String[] cvm = (cur == arr1)?arr2:arr1;
                int index = tmp.indexOf(cur[0]);
                int index2 = tmp.indexOf(cur[1]);
                if(index + index2 == 60){//说明其中一个是王炸
                    if(cur == arr1){
                        return s1;
                    }else {
                        return s2;
                    }
                }else if(index == index2 && cvm.length == 4){//判断是否一个为对子,一个为炸弹
                    String kvl = cvm[0];
                    for (int i = 0; i < cvm.length; i++) {
                        if(!cvm[i].equals(kvl)){
                            return ret;
                        }
                    }
                    if(cvm == arr1){
                        return s1;
                    }else {
                        return s2;
                    }
                }
            }else {//不存在王炸,判断是否存在炸弹
                if(arr1.length == 4 || arr2.length == 4){
                    String[] ynm = new String[4];
                    if(arr1.length == 4){
                        ynm = arr1;
                    }else {
                        ynm = arr2;
                    }
                    String kkl = ynm[0];
                    for (int i = 0; i < ynm.length; i++) {
                        if(!ynm[i].equals(kkl)){
                            return ret;
                        }
                    }
                    if(ynm == arr1){
                        return s1;
                    }else {
                        return s2;
                    }
                }
            }
        }else {
            int res = judgeSame(arr1[0],arr2[0]);
            if(res == 1){
                return s1;
            }else {
                return s2;
            }
        }
        return ret;
    }
    private static int judgeSame(String s1,String s2){
        int index = tmp.indexOf(s1);
        int index2 = tmp.indexOf(s2);
        int result = 1;
        if(index < index2){
            result = -1;
        }
        return result;
    }
}
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