0
点赞
收藏
分享

微信扫一扫

4.25作业

九点韶留学 2022-04-25 阅读 59
sql

1.

# 作业 4月 25 日
CREATE TABLE dept (
  id INT PRIMARY KEY PRIMARY KEY, -- 部门id
  dname VARCHAR(50), -- 部门名称
  loc VARCHAR(50) -- 部门所在地
);

-- 添加4个部门
INSERT INTO dept(id,dname,loc) VALUES 
(10,'教研部','北京'),
(20,'学工部','上海'),
(30,'销售部','广州'),
(40,'财务部','深圳');

-- 职务表,职务名称,职务描述
CREATE TABLE job (
  id INT PRIMARY KEY,
  jname VARCHAR(20),
  description VARCHAR(50)
);
 
-- 添加4个职务
INSERT INTO job (id, jname, description) VALUES
(1, '董事长', '管理整个公司,接单'),
(2, '经理', '管理部门员工'),
(3, '销售员', '向客人推销产品'),
(4, '文员', '使用办公软件');
 
 
 
-- 员工表
CREATE TABLE emp (
  id INT PRIMARY KEY, -- 员工id
  ename VARCHAR(50), -- 员工姓名
  job_id INT, -- 职务id
  mgr INT , -- 上级领导
  joindate DATE, -- 入职日期
  salary DECIMAL(7,2), -- 工资
  bonus DECIMAL(7,2), -- 奖金
  dept_id INT, -- 所在部门编号
  CONSTRAINT emp_jobid_ref_job_id_fk FOREIGN KEY (job_id) REFERENCES job (id),
  CONSTRAINT emp_deptid_ref_dept_id_fk FOREIGN KEY (dept_id) REFERENCES dept (id)
);
 
-- 添加员工
INSERT INTO emp(id,ename,job_id,mgr,joindate,salary,bonus,dept_id) VALUES 
(1001,'孙悟空',4,1004,'2000-12-17','8000.00',NULL,20),
(1002,'卢俊义',3,1006,'2001-02-20','16000.00','3000.00',30),
(1003,'林冲',3,1006,'2001-02-22','12500.00','5000.00',30),
(1004,'唐僧',2,1009,'2001-04-02','29750.00',NULL,20),
(1005,'李逵',4,1006,'2001-09-28','12500.00','14000.00',30),
(1006,'宋江',2,1009,'2001-05-01','28500.00',NULL,30),
(1007,'刘备',2,1009,'2001-09-01','24500.00',NULL,10),
(1008,'猪八戒',4,1004,'2007-04-19','30000.00',NULL,20),
(1009,'罗贯中',1,NULL,'2001-11-17','50000.00',NULL,10),
(1010,'吴用',3,1006,'2001-09-08','15000.00','0.00',30),
(1011,'沙僧',4,1004,'2007-05-23','11000.00',NULL,20),
(1012,'李逵',4,1006,'2001-12-03','9500.00',NULL,30),
(1013,'小白龙',4,1004,'2001-12-03','30000.00',NULL,20),
(1014,'关羽',4,1007,'2002-01-23','13000.00',NULL,10);
 
 
 
 
-- 工资等级表
CREATE TABLE salarygrade (
  grade INT PRIMARY KEY,   -- 级别
  losalary INT,  -- 最低工资
  hisalary INT -- 最高工资
);
 
-- 添加5个工资等级
INSERT INTO salarygrade(grade,losalary,hisalary) VALUES 
(1,7000,12000),
(2,12010,14000),
(3,14010,20000),
(4,20010,30000),
(5,30010,99990);


select * from dept;
select * from job;
select * from emp;
select * from salarygrade;


-- 1.查询所有员工信息。查询员工编号,员工姓名,工资,职务名称,职务描述
select e.id , e.ename , e.salary ,j.jname , j.description
from emp e , job j
where  e.job_id = j.id 
-- 2.查询员工编号,员工姓名,工资,职务名称,职务描述,部门名称,部门位置
select e.id , e.ename , e.salary ,j.jname ,j.description , d.dname , d.loc
from emp e , job j , dept d 
where e.job_id = j.id and e.dept_id = d.id
-- 3.查询员工姓名,工资,工资等级
select e.ename , e.salary , s.grade
from emp e , salarygrade s
where e.salary > s.losalary and e.salary < s.hisalary
-- 4.查询员工姓名,工资,职务名称,职务描述,部门名称,部门位置,工资等级
select e.ename , e.salary , j.jname , j.description , d.dname , d.loc , s.grade
from emp e , job j , dept d , salarygrade s
where e.job_id = j.id and e.dept_id = d.id and e.salary between s.losalary and s.hisalary;
-- 5.查询出部门编号,部门名称,部门位置,部门人数
-- 部门人数 select dept_id,count(id) total from emp group by dept_id;
select d.id , d.dname , d.loc , c.total
from dept d , ( select dept_id,count(id) total from emp group by dept_id) c
where d.id = c.dept_id;
-- 6.查询所有员工的姓名及直接上级的姓名,没有领导的员工也需要查询

select e.ename , e.mgr , e2.id , e2.ename
from emp e left join emp e2
on e.mgr = e2.id;
举报

相关推荐

0 条评论