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1207. Unique Number of Occurrences*

1207. Unique Number of Occurrences*

​​https://leetcode.com/problems/unique-number-of-occurrences/​​

题目描述

Given an array of integers ​​arr​​​, write a function that returns ​​true​​ if and only if the number of occurrences of each value in the array is unique.

Example 1:

Input: arr = [1,2,2,1,1,3]
Output: true
Explanation: The value 1 has 3 occurrences, 2 has 2 and 3 has 1. No two values have the same number of occurrences.

Example 2:

Input: arr = [1,2]
Output: false

Example 3:

Input: arr = [-3,0,1,-3,1,1,1,-3,10,0]
Output: true

Constraints:

  • ​1 <= arr.length <= 1000​
  • ​-1000 <= arr[i] <= 1000​

C++ 实现 1

判断每个元素出现的个数是不是 unique 的.

使用两个哈希表, 一个记录每个元素的个数, 另一个判断是否出现的个数是 unique 的.

class Solution {
public:
bool uniqueOccurrences(vector<int>& arr) {
unordered_map<int, int> record;
unordered_set<int> nums;
for (auto &c : arr)
record[c] ++;
for (auto &p : record) {
if (nums.count(p.second)) return false;
nums.insert(p.second);
}
return true;
}
};

C++ 实现 2

或者这样写, 来自 LeetCode Submission

class Solution {
public:
bool uniqueOccurrences(vector<int>& arr) {
unordered_map<int, int> m;
unordered_set<int> s;
for (auto n : arr) ++m[n];
for (auto& p : m) s.insert(p.second);
return m.size() == s.size();
}
};

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