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刷题二


实现带有重复元素的二分查找,如果查找的元素重复,返回重复元素的起始位置。


#include <iostream>
#include <vector>
using namespace std;

class Solution{
    public:
    int binarySearch(vector<int> & array, int target){
        if(array.size() == 0)
            return -1;
        else if(array.size() == 1)
            return 0;
        else{
            int low = 0, high = array.size() - 1;
            int mid = 0;
            while(low < high && low < array.size() && high >= 0){
                mid = (low + high) / 2;
                if(array[mid] == target && (mid == 0 || array[mid - 1] != target)){
                        return mid;
                }
                else if(array[mid] >= target)
                    high = mid - 1;
                else
                    low = mid + 1;
            }
        }
        return -1;
    }
};
int main() {
	cout  << "test\n";
	int arrayTemp[] = {1,2,3,3,5,6,6,6,8,10};
	vector<int> array(arrayTemp,arrayTemp + 10);
	Solution sol;
	int result = sol.binarySearch(array,3);
	if(result == -1)
	    cout << "fail to find" << endl;
	else
	    cout << result << endl;
	return 0;
}




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