#coding=utf-8
"""
===========================
Author:多测师_王sir
Time:2020-07-14 15:57
===========================
"""
#企业笔试代码题: 有一个字符串X,求字符串X中字母a的位置和数量??
str = "abcabcaaduoceshi"
list1 = []
num = 0
while str:
i = str.find("a", num)
if not i == -1:
num = i + 1
list1.append(i)
else:
break
print 'a的索引为{0[0]} {0[1]} {0[2]} {0[3]}'.format(list1)
print 'a出现的次数为{}次'.format(len(list1))
答案如下:
a的索引为0 3 6 7
a出现的次数为4次