官网给的例子只能搜索树形图中与关键字匹配的级别:
<el-input
placeholder="输入关键字进行过滤"
v-model="filterText">
</el-input>
<el-tree
class="filter-tree"
:data="data2"
:props="defaultProps"
default-expand-all
:filter-node-method="filterNode"
ref="tree2">
</el-tree>
<script>
export default {
watch: {
filterText(val) {
this.$refs.tree2.filter(val);
}
},
methods: {
filterNode(value, data) {
if (!value) return true;
return data.label.indexOf(value) !== -1;
}
},
data() {
return {
filterText: '',
data2: [{
id: 1,
label: '一级 1',
children: [{
id: 4,
label: '二级 1-1',
children: [{
id: 9,
label: '三级 1-1-1'
}, {
id: 10,
label: '三级 1-1-2'
}]
}]
}, {
id: 2,
label: '一级 2',
children: [{
id: 5,
label: '二级 2-1'
}, {
id: 6,
label: '二级 2-2'
}]
}, {
id: 3,
label: '一级 3',
children: [{
id: 7,
label: '二级 3-1'
}, {
id: 8,
label: '二级 3-2'
}]
}],
defaultProps: {
children: 'children',
label: 'label'
}
};
}
};
</script>
使用改进的方法可以搜索出一整条路径:
filterNode(value,data,node) {
if(!value){
return true;
}
let level = node.level;
let _array = [];//这里使用数组存储 只是为了存储值。
this.getReturnNode(node,_array,value);
let result = false;
_array.forEach((item)=>{
result = result || item;
});
return result;
},
getReturnNode(node,_array,value){
let isPass = node.data && node.data.label && node.data.label.indexOf(value) !== -1;
isPass?_array.push(isPass):'';
this.index++;
console.log(this.index)
if(!isPass && node.level!=1 && node.parent){
this.getReturnNode(node.parent,_array,value);
}
},