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Leetcode 459. 重复的子字符串 Repeated Substring Pattern - Python KMP算法求next数组

最不爱吃鱼 2022-03-26 阅读 80
class Solution:
    def repeatedSubstringPattern(self, s: str) -> bool:
        l = len(s)
        next = self.getNext(s)
        if next[l-1] != 0 and l % ( l- next[l-1]) == 0:
            return True        #重复某一字段构成的数组的特点可以被if条件检查出来 abcdabcdabcd
        else:
            return False

    def getNext(self,s):
        l = len(s)
        j = 0
        next = [0 for x in range(l)]
        for i in range(1,l):
            while s[j] != s[i] and j > 0:
                j = next[j-1]
            if s[j]==s[i]:
                j += 1
            next[i] = j
        return next

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