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found character ‘@‘ that cannot start any token

霸姨 2022-09-13 阅读 201


问题内容如下

ERROR org.springframework.boot.SpringApplication - Application run failed
org.yaml.snakeyaml.scanner.ScannerException: while scanning for the next token
found character '@' that cannot start any token. (Do not use @ for indentation)
in 'reader', line 6, column 9:
name: @name@

对应问题application.yml

app:
java:
# 引用pom.xml文件中的属性
version: @java.version@
sourceEncoding: @project.build.sourceEncoding@
name: @name@
version:

解决方法

将@@用单引号引起来,修改后的内容如下

app:
java:
# 引用pom.xml文件中的属性
version: '@java.version@'
sourceEncoding: '@project.build.sourceEncoding@'
name: '@name@'
version: '@version@'


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