HDOJ 2054 A == B ?【大数】

A == B ?

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 51920 Accepted Submission(s): 8014

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Input

each test case contains two numbers A and B.

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input

1 2 2 2 3 3 4 3

Sample Output

NO YES YES NO

<pre name="code" class="java">import java.math.BigDecimal;
import java.math.BigInteger;
import java.math.MathContext;
import java.util.Scanner;
public class Main{
    public static void main(String args[]){
        Scanner cin = new Scanner(System.in);
        while(cin.hasNext()){
            BigDecimal a = cin.nextBigDecimal();
            BigDecimal b = cin.nextBigDecimal();
            if(a.equals(BigDecimal.valueOf(0.0)))
                a = BigDecimal.ZERO;
            if(b.equals(BigDecimal.valueOf(0.0)))
                b = BigDecimal.ZERO;
            if(a.stripTrailingZeros().toPlainString().equals(b.stripTrailingZeros().toPlainString()))
                System.out.println("YES");
            else {
                System.out.println("NO");
            }
        }
        cin.close();
    }
}

#include<stdio.h>
#include<string.h>
char *removepoint(char a[])//不用考虑前导0...这让我很困惑啊..Dev结果都不对还能AC
{
  int len = strlen(a);
  //strchr的功能 ： 
  //返回首次出现c的位置的指针，返回的地址是字符串在内存中
  //随机分配的地址再加上你所搜索的字符在字符串位置，如果s中不存在c则返回NULL 
  if(strchr(a,'.')!=NULL)
  {
    while(a[--len] == '0');
    if(a[len]=='.') len--;
    a[len+1] = '\0';
  }
  return a;
}
int main()
{
  char a[15000],b[15000];
  while(~scanf("%s%s",a,b))
  {
    if(strcmp(removepoint(a),removepoint(b))==0) printf("YES\n");
    else printf("NO\n");
  }
  return 0;
}