Bone Collector(01背包问题)-CFANZ编程社区

Bone Collector(01背包问题)

Bone Collector Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 81002 Accepted Submission(s): 33501 Problem Description Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s , also he went to the grave … The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ? Input The first line contain a integer T , the number of cases. Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone. Output One integer per line representing the maximum of the total value (this number will be less than 231). Sample Input 1 5 10 1 2 3 4 5 5 4 3 2 1 Sample Output 14

第一行一个t 表示t 组测试数据

第二行 n 和 V 表示骨头的数目和背包的体积

第三行是骨头的价值

第四行是骨头的体积

每个骨头只能拿一个

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
using namespace std;

const int maxn=1e3+9;
int w[maxn],v[maxn],dp[maxn];

int main()
{
  int t;
  int n,W;
  scanf("%d",&t);
  while(t--)
  {
    memset(dp,0,sizeof(dp));
    scanf("%d %d",&n,&W);
    for(int i=0;i<n;i++)
      scanf("%d",&v[i]);
    for(int i=0;i<n;i++)
      scanf("%d",&w[i]);
    for(int i=0;i<n;i++)
      for(int j=W;j>=w[i];j--)
        dp[j]=max(dp[j],dp[j-w[i]]+v[i]);
    printf("%d\n",dp[W]);
  }
  return 0;
}

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