There is a box protected by a password. The password is n digits, where each letter can be one of the first k digits 0, 1, …, k-1.
You can keep inputting the password, the password will automatically be matched against the last n digits entered.
For example, assuming the password is “345”, I can open it when I type “012345”, but I enter a total of 6 digits.
Please return any string of minimum length that is guaranteed to open the box after the entire string is inputted.
Example 1:
Input: n = 1, k = 2
Output: "01"
Note: "10" will be accepted too.
Example 2:
Input: n = 2, k = 2
Output: "00110"
Note: "01100", "10011", "11001"
Note:
n will be in the range [1, 4].
k will be in the range [1, 10].
k^n will be at most 4096.
class Solution {
public String crackSafe(int n, int k) {
int M = (int) Math.pow(k, n-1);
int[] P = new int[M * k];
for (int i = 0; i < k; ++i)
for (int q = 0; q < M; ++q)
P[i*M + q] = q*k + i;
StringBuilder ans = new StringBuilder();
for (int i = 0; i < M*k; ++i) {
int j = i;
while (P[j] >= 0) {
ans.append(String.valueOf(j / M));
int v = P[j];
P[j] = -1;
j = v;
}
}
for (int i = 0; i < n-1; ++i)
ans.append("0");
return new String(ans);
}
}