c++pat1057(分块)

Stack is one of the most fundamental data structures, which is based on the principle of Last In First Out (LIFO). The basic operations include Push (inserting an element onto the top position) and Pop (deleting the top element). Now you are supposed to implement a stack with an extra operation: PeekMedian – return the median value of all the elements in the stack. With N elements, the median value is defined to be the (N/2)-th smallest element if N is even, or ((N+1)/2)-th if N is odd.

Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (≤10 5 ). Then N lines follow, each contains a command in one of the following 3 formats:

Push key
Pop
PeekMedian
where key is a positive integer no more than 10 5

Output Specification:
For each Push command, insert key into the stack and output nothing. For each Pop or PeekMedian command, print in a line the corresponding returned value. If the command is invalid, print Invalid instead.

Sample Input:

17
Pop
PeekMedian
Push 3
PeekMedian
Push 2
PeekMedian
Push 1
PeekMedian
Pop
Pop
Push 5
Push 4
PeekMedian
Pop
Pop
Pop
Pop

Sample Output:

Invalid
Invalid
3
2
2
1
2
4
4
5
3
Invalid

核心思路

分块思想来做，也不简单，栈空如果还操作记得返回invalid

完整源码

#include<cstdio>
#include<cstring>
#include<stack>
using namespace std;
const int maxn = 100010;
const int sqrN = 316;

stack<int> st;
int block[sqrN];//记录每一块中存在的元素个数
int table[maxn];//hash数组，记录元素当前存在个数

void peekMedian(int K){
    int sum = 0;
    int idx = 0;
    while(sum + block[idx] < K){
        sum += block[idx++];
    }
    int num = idx * sqrN;
    while(sum + table[num] < K){
        sum += table[num++];
    }
    printf("%d\n",num);
}

void Push(int x){
    st.push(x);
    block[x/sqrN]++;//x所在的块的元素个数加1
    table[x]++; //x的存在个数加1
}

void Pop(){
    int x = st.top();
    st.pop();
    block[x/sqrN]--;
    table[x]--;
    printf("%d\n",x);
}

int main(){
    int x,query;
    memset(block,0,sizeof(block));
    memset(table,0,sizeof(table));
    char cmd[20];
    scanf("%d",&query);
    for(int i =0;i<query;i++){
        scanf("%s",cmd);
        if(strcmp(cmd,"Push")==0){
            scanf("%d",&x);
            Push(x);
        }else if(strcmp(cmd,"Pop") == 0){
            if(st.empty() == true){
                printf("Invalid\n");
            }else{
                Pop(); //出栈
            }
        }else{
            if(st.empty() == true){
                printf("Invalid\n");
            }else{
                int K = st.size();
                if(K%2==1) K = (K+1)/2;
                else K = K /2;
                peekMedian(K);
            }
        }
    }
    return 0;
}