题目描述:
给定一个二叉树,返回它的中序 遍历。
示例:
输入: [1,null,2,3]
1
\
2
/
3
输出: [1,3,2]
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> res;
void inorder(TreeNode* root){
if(root==NULL)
return ;
inorder(root->left);
res.push_back(root->val);
inorder(root->right);
}
vector<int> inorderTraversal(TreeNode* root) {
inorder(root);
return res;
}
};
非递归算法:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<int> res;
stack<TreeNode*> temp;
vector<int> inorderTraversal(TreeNode* root) {
TreeNode* p=root;
while(p||!temp.empty()){
if(p){
temp.push(p);
p=p->left;
continue;
}else{
TreeNode* node=temp.top();
int x=node->val;
temp.pop();
res.push_back(x);
p=node->right;
}
}
return res;
}
};