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C/C++ 任意位设置0/1,位取反

Sky飞羽 2022-01-26 阅读 54
c++

 整形数据任意位置0/1:SetBit(data,n,val);

data:整形数据;

n:整形数据第n位 置0/1;

val: 取值0/1;

整形数据任意位取反:RevBit(data,n);

data:整形数据;

n:整形数据第n位 取反; 

#define SetBit(data,n,val) (((val)==1)?((data)|(1<<(n))):((data)&~(1<<(n))))
#define RevBit(data,n) ((data)^(1<<(n)))

 测试代码:

#include "stdafx.h"
#include <iostream>

using namespace std;
#pragma warning(disable:4996)

#define SetBit(data,n,val) (((val)==1)?((data)|(1<<(n))):((data)&~(1<<(n))))
#define RevBit(data,n) ((data)^(1<<(n)))

int _tmain(int argc, _TCHAR* argv[])
{
	cout<<"RevBit(7,0) = "<<RevBit(7,0)<<endl;
	cout<<"RevBit(7,1) = "<<RevBit(7,1)<<endl;
	cout<<"RevBit(7,2) = "<<RevBit(7,2)<<endl;
	cout<<"RevBit(6,0) = "<<RevBit(6,0)<<endl;
	cout<<"RevBit(5,1) = "<<RevBit(5,1)<<endl;
	cout<<"RevBit(3,2) = "<<RevBit(3,2)<<endl;
	cout<<endl;
	cout<<"SetBit(0,0,1) = "<<SetBit(0+1,0+0,1+0)<<endl;
	cout<<"SetBit(0,1,1) = "<<SetBit(0+1,1+0,1+0)<<endl;
	cout<<"SetBit(0,2,1) = "<<SetBit(0+1,1+1,1+0)<<endl;
	cout<<"SetBit(6,0,1) = "<<SetBit(6,0,1)<<endl;
	cout<<"SetBit(5,1,1) = "<<SetBit(5,1,1)<<endl;
	cout<<"SetBit(3,2,1) = "<<SetBit(3,2,1)<<endl;
	cout<<endl;									
	cout<<"SetBit(7,0,0) = "<<SetBit(7,0,0)<<endl;
	cout<<"SetBit(7,1,0) = "<<SetBit(7,1,0)<<endl;
	cout<<"SetBit(7,2,0) = "<<SetBit(7,2,0)<<endl;
	cout<<"SetBit(6,0,0) = "<<SetBit(6,0,0)<<endl;
	cout<<"SetBit(5,1,0) = "<<SetBit(5,1,0)<<endl;
	cout<<"SetBit(3,2,0) = "<<SetBit(3,2,0)<<endl;
	
	getchar();
	return 0;
}

测试结果:

 

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