1、題目內容: 从键盘输入一个整形数n,如果输入正确的话,输出1-n的值,如果输入错误的话输出“not int” 最后输出end
输入输出说明:
输入: asd
输出: not int end
try { Scanner sc=new Scanner(System.in); System.out.println("请输入一个整数"); int i = sc.nextInt(); int a=0; for (int j = 1; j <=i ; j++) { System.out.print(j+" "); a++; if (a%20==0){ System.out.println(); } } System.out.println(); } catch (Exception v){ System.out.println("not int"); }finally { System.out.println("end"); }
2、題目內容: 模拟向货船上装载集装箱,每个集装箱有一定重量,该重量(整数)大于100小于1000,货船总重为1000, 装载若干集装箱后,如果货船超重,那么货船认为这是一个异常,将拒绝装载集装箱, 但无论是否发生异常,货船都需要正点启航
public static void main(String[] args)throws MyExtiom { Lunchuan lunchuan = new Lunchuan(); try { for (;;) { int i = (int) (Math.random() * 901 + 100); lunchuan.zhuangHuo(i); } } catch (MyExtiom extiom){ System.out.println("货物超重,拒绝装船"); }finally { System.out.println("启航"); } } } class MyExtiom extends Exception{ public MyExtiom() { } public MyExtiom(String message) { super(message); } } class Lunchuan{ private int weight=1000; public void zhuangHuo(int weight) throws MyExtiom { int a=this.weight+weight; if (a>80000){ throw new MyExtiom("货物超重,拒绝装船"); }else { this.weight=a; } } public int getWeight() { return weight; } public void setWeight(int weight) { this.weight = weight; } }
3、递归删除某个目录下的所有的文件 提示: delete()方法只能删除文件,不能删除文件夹 模仿课上讲的遍历指定目录及其子目录的方式
public static void main(String[] args) { String path="D:/qiku/测试"; File file=new File(path); File[] files = file.listFiles(); System.out.println(Arrays.toString(files)); delight(file); files=file.listFiles(); System.out.println(Arrays.toString(files)); } public static void delight(File file){ File[] files = file.listFiles(); for (int i=0;i<files.length;i++){ File f=files[i]; if (f.isFile()){ f.delete(); }else { delight(f); f.delete();//删除文件夹 } } }