0
点赞
收藏
分享

微信扫一扫

134. Gas Station

時小白 2022-08-03 阅读 19


There are N gas stations along a circular route, where the amount of gas at station i is gas[i].

You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations.

Return the starting gas station’s index if you can travel around the circuit once, otherwise return -1.

Note:
The solution is guaranteed to be unique.

class Solution {
public int canCompleteCircuit(int[] gas, int[] cost) {
if (gas == null || cost == null || gas.length == 0 || cost.length == 0) {
return -1;
}

int sum = 0;
int total = 0;
int index = -1;

for(int i = 0; i<gas.length; i++) {
sum += gas[i] - cost[i];
total += gas[i] - cost[i];
if(sum < 0) {
index = i;
sum = 0;
}
}
return total < 0 ? -1 : index + 1;
// index should be updated here for cases ([5], [4]);
// total < 0 is for case [2], [2]
}
}

class Solution {
public int canCompleteCircuit(int[] gas, int[] cost) {
int currentNetSum = 0;
int startIdx = -1;
int totalNetDiff = 0;

for(int idx = 0; idx < gas.length; idx++) {
int currentDiff = gas[idx] - cost[idx];
currentNetSum += currentDiff;
totalNetDiff += currentDiff;
if(currentNetSum < 0) {
currentNetSum = 0;
startIdx = -1;
continue;
}

startIdx = startIdx == -1 ? idx: startIdx;
}

return startIdx != -1 && totalNetDiff >= 0 ? startIdx: -1;
}
}


举报

相关推荐

0 条评论