暴力。。。然后判断是否为立方体时。。。先求出中心,然后通过经过中心的所有边的长度是否相等来判断是否为立方体。。。
#include <iostream>
#include <queue>
#include <stack>
#include <map>
#include <set>
#include <bitset>
#include <cstdio>
#include <algorithm>
#include <cstring>
#include <climits>
#include <cstdlib>
#include <cmath>
#include <time.h>
#define maxn 400005
#define maxm 400005
#define eps 1e-10
#define mod 1000000007
#define INF 999999999
#define lowbit(x) (x&(-x))
#define mp mark_pair
#define ls o<<1
#define rs o<<1 | 1
#define lson o<<1, L, mid
#define rson o<<1 | 1, mid+1, R
//typedef vector<int>::iterator IT;
typedef long long LL;
//typedef int LL;
using namespace std;
LL qpow(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base;base=base*base;b/=2;}return res;}
LL powmod(LL a, LL b){LL res=1,base=a;while(b){if(b%2)res=res*base%mod;base=base*base%mod;b/=2;}return res;}
void scanf(int &__x){__x=0;char __ch=getchar();while(__ch==' '||__ch=='\n')__ch=getchar();while(__ch>='0'&&__ch<='9')__x=__x*10+__ch-'0',__ch = getchar();}
LL gcd(LL _a, LL _b){if(!_b) return _a;else return gcd(_b, _a%_b);}
// head
int a[10], b[10], c[10], ok;
bool check(void)
{
int aa, bb, cc;
aa = bb = cc = 0;
for(int i = 1; i <= 8; i++) aa += a[i], bb += b[i], cc += c[i];
if(aa%4 || bb%4 || cc%4) return false;
aa /= 4, bb /= 4, cc /= 4;
LL t = 0;
for(int i = 1; i <= 8; i++) {
int flag = 1;
LL tt;
for(int j = 1; j <= 8 && flag; j++)
if(a[i] + a[j] == aa && b[i] + b[j] == bb && c[i] + c[j] == cc) {
flag = 0;
tt = (LL)(a[j] - a[i])*(a[j] - a[i]) + (LL)(b[j] - b[i])*(b[j] - b[i]) + (LL)(c[j] - c[i])*(c[j] - c[i]);
}
if(flag) return false;
if(!t) t = tt;
else if(t != tt) return false;
}
return true;
}
bool safe(void)
{
for(int i = 1; i <= 8; i++)
for(int j = i+1; j <= 8; j++)
if(a[i] == a[j] && b[i] == b[j] && c[i] == c[j]) return false;
return true;
}
void dfs(int now)
{
if(now == 9) {
if(safe() && check()) ok = 0;
return;
}
for(int i = 1; i <= 6 && ok; i++)
if(i%2 == 1) swap(b[now], c[now]), dfs(now+1);
else swap(a[now], b[now]), dfs(now+1);
}
int main(void)
{
for(int i = 1; i <= 8; i++) scanf("%d%d%d", &a[i], &b[i], &c[i]);
ok = 1, dfs(1);
if(ok) printf("NO\n");
else {
printf("YES\n");
for(int i = 1; i <= 8; i++) printf("%d %d %d\n", a[i], b[i], c[i]);
}
return 0;
}