492. Construct the Rectangle

For a web developer, it is very important to know how to design a web page’s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.

3. The difference between length L and width W should be as small as

You need to output the length L and the width W of the web page you designed in sequence.
Example:

Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

Note:
The given area won’t exceed 10,000,000 and is a positive integer
The web page’s width and length you designed must be positive integers.

public class Solution {
    public int[] constructRectangle(int area) {
        int[] res = new int[2];
        int w = 0;
        int l = 0;
        for(int i = 1;i <= (int)Math.sqrt(area);i++){
            if(area % i == 0){
                w = i;
                l = area / i;
            }
        }
        res[0] = l;
        res[1] = w;
        return