每日一题-LeetCode883-三维形体投影面积-数学-几何

原题链接

每个方向进行遍历，找到最大值就好了 代码如下：

class Solution {
public:
    int projectionArea(vector<vector<int>>& grid) {
        int ans = 0;
        int x = 0, y = 0, o = 0;
        int n = grid.size();
        if(!n)  return 0;
        int m = grid[0].size();
        for(int i = 0; i < n; i ++)
            for(int j = 0; j < m; j ++)
                if(grid[i][j] != 0)
                o ++;
        
        for(int i = 0; i < n; i ++){
            int k = INT_MIN;
            for(int j = 0; j < m; j ++)
                k = max(k, grid[i][j]);
            x += k;
        }

        for(int i = 0; i < m; i ++){
            int k = INT_MIN;
            for(int j = 0; j < n; j ++)
                k = max(k, grid[j][i]);
            y += k;
        }

        ans = o + x + y;
        
        return ans;
    }
};