74. Search a 2D Matrix**
https://leetcode.com/problems/search-a-2d-matrix/
题目描述
Write an efficient algorithm that searches for a value in an m x n
matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
Example 1:
Input:
matrix = [
[1, 3, 5, 7],
[10, 11, 16, 20],
[23, 30, 34, 50]
]
target = 3
Output: true
Example 2:
Input:
matrix = [
[1, 3, 5, 7],
[10, 11, 16, 20],
[23, 30, 34, 50]
]
target = 13
Output: false
解题思路
把二维矩阵当成一维的 list 即可, 使用二分查找.
C++ 实现 1
class Solution {
public:
bool searchMatrix(vector<vector<int>>& matrix, int target) {
if (matrix.empty() || matrix[0].empty()) return false;
int m = matrix.size(), n = matrix[0].size();
int i = 0, j = m * n - 1;
while (i <= j) {
int mid = i + (j - i) / 2;
int p = mid / n, q = mid % n;
if (matrix[p][q] == target) return true;
else if (matrix[p][q] < target) ++ i;
else -- j;
}
return false;
}
};