74. Search a 2D Matrix

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

Integers in each row are sorted from left to right.
The first integer of each row is greater than the last integer of the previous row.
Example 1:

Input:
matrix = [
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]
target = 3
Output: true

Example 2:

Input:
matrix = [
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]
target = 13
Output: false

public class Solution {
     public boolean searchMatrix(int[][] matrix, int target) {
        // write your code here
        if(matrix == null || matrix.length == 0){
            return false;
        }
        
        if(matrix[0] == null || matrix[0].length == 0){
            return false;
        }
        
        int row = matrix.length;
        int column = matrix[0].length;
        
        int start = 0, end = row * column - 1;
        while(start <= end){
            int mid = start + (end - start) / 2;
            int number = matrix[mid / column][mid % column];
            if(number == target){
                return true;
            }else if(number > target){
                end = mid - 1;
            }else{
                start = mid + 1;
            }
        }
        
        return false;
        
    }

}

class Solution {
    public boolean searchMatrix(int[][] matrix, int target) {
        for(int i = 0; i < matrix.length; i++) {
            if(matrix[i].length > 0 && target >= matrix[i][0] && target <= matrix[i][matrix[i].length - 1]) {
                return Arrays.binarySearch(matrix[i], target) >= 0 ? true : false;
            }
        }
        return false;
    }
}