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UVa 1328 Period (KMP&失配函数的理解)


http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=505&page=show_problem&problem=4074


令失配函数为f[i],由失配函数的定义可知i-f[i]就是最小重复子串的长度。


完整代码:

/*0.066s*/

#include<cstdio>
const int maxn = 1000005;

char P[maxn];
int f[maxn];

int main()
{
	int n, kase = 0;
	while (scanf("%d", &n), n)
	{
		getchar();
		gets(P);
		f[0] = f[1] = 0;
		for (int i = 1; i < n; i++)
		{
			int j = f[i];
			while (j && P[i] != P[j]) j = f[j];
			f[i + 1] = (P[i] == P[j] ? j + 1 : 0);
		}
		printf("Test case #%d\n", ++kase);
		for (int i = 2; i <= n; i++)
			if (f[i] && i % (i - f[i]) == 0)
				printf("%d %d\n", i, i / (i - f[i]));
		putchar(10);
	}
	return 0;
}


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