题目链接:点击打开链接
题目大意:略。
解题思路:略。
AC 代码
-- 解决方案(1)
WITH t1 AS(SELECT *
FROM my_numbers
GROUP BY num
HAVING COUNT(*) = 1
ORDER BY num DESC
LIMIT 1)
SELECT IF(COUNT(*) = 0, null, num) AS `num`
FROM t1
-- 解决方案(2)
SELECT
MAX(num) AS num
FROM
(SELECT
num
FROM
number
GROUP BY num
HAVING COUNT(num) = 1) AS t
;