爬楼梯
问题解析
解法一:递归
解法二:迭代
public class LeetCode_070 {
/**
* 递归:提交时超出时间限制了
*
* @param n
* @return
*/
public static int climbStairs(int n) {
if (n == 1 || n == 2) {
return n;
}
return climbStairs(n - 1) + climbStairs(n - 2);
}
/**
* 迭代
*
* @param n
* @return
*/
public static int climbStairs2(int n) {
if (n == 1 || n == 2) {
return n;
}
int lastOne = 1, lastTwo = 2, result = -1;
for (int i = 3; i <= n; i++) {
result = lastOne + lastTwo;
lastOne = lastTwo;
lastTwo = result;
}
return result;
}
public static void main(String[] args) {
System.out.println(climbStairs(45));
System.out.println(climbStairs2(45));
}
}