Problem Description
A ring is compose of n circles as shown in diagram. Put natural number 1, 2, ..., n into each circle separately, and the sum of numbers in two adjacent circles should be a prime.
Note: the number of first circle should always be 1.
Input
n (0 < n < 20).
Output
The output format is shown as sample below. Each row represents a series of circle numbers in the ring beginning from 1 clockwisely and anticlockwisely. The order of numbers must satisfy the above requirements. Print solutions in lexicographical order.
You are to write a program that completes above process.
Print a blank line after each case.
Sample Input
6 8
Sample Output
1 6 7 4 3 8 5 2
这里是一个典型的深搜问题,这里如果用Boolean打表,调用import java.util.Arrays;在杭电上提交会超时
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
int Case=0;
Scanner sc = new Scanner(System.in);
while(sc.hasNext()){
int n= sc.nextInt();
int color[] = new int[n];
int arr[] = new int[n];
int prant[] = new int [n];
int count=0; //Arrays.fill(color,false);
for(int i=0;i<arr.length;i++){
arr[i]=i+1; //初始化所有数据
color[i]=-1;
}
Case++;
System.out.println("Case "+(Case)+":");
dfs(arr,color,prant,count,0);
System.out.println();
}
}
public static void dfs(int[] arr,int[] color,int[] prant,int count,int m){
count++;
if(count==arr.length && prime(prant[0],arr[m])){ //第一个数与最后一个数相加的和也是素数
prant[count-1] = arr[m];
for(int i=0;i<arr.length-1;i++){
System.out.print(prant[i]+" ");
}
System.out.println(prant[arr.length-1]);
}
for(int i=0;i<arr.length;i++){
color[m]=1;
if(prime(arr[m],arr[i]) && color[i]==-1){
color[i]=1; prant[count-1]=arr[m];
dfs(arr,color,prant,count,i);
color[i]=-1;
}
}
}
//判断素数
public static boolean prime(int i,int j){
int sum=i+j;
for(int k=2;k*k<=sum;k++){
if(sum%k==0){
return false;
}
}
return true;
}
}